The position of a projectile launched from the origin at $t = 0$ is given by $\vec r = \left( {40\hat i + 50\hat j} \right)\,m$ at $t = 2\,s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g = 10\, ms^{-2}$)

  • [JEE MAIN 2014]
  • A

    ${\tan ^{ - 1}}\frac{2}{3}$

  • B

    ${\tan ^{ - 1}}\frac{3}{2}$

  • C

    ${\tan ^{ - 1}}\frac{7}{4}$

  • D

    ${\tan ^{ - 1}}\frac{4}{5}$

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